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The addition of excess of aqueous HNO3 to a solution containing [Cu(NH3)4]^2+ produces:
- Cu^+
- [Cu(H2O)4]^2+
- Cu(OH)
- Cu(NO3)2
Correct answer: [Cu(H2O)4]^2+
Solution
Excess HNO3 provides H+ ions, which displace NH3 ligands from [Cu(NH3)4]^2+, forming [Cu(H2O)4]^2+ as the stable complex in aqueous solution.
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