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In acidic medium, H2O2 changes Cr2O7^2− to CrO5 which has two (O−O) bonds. Oxidation state of Cr in CrO5 is:

1. +5
2. +3
3. +6
4. −10

Correct answer: +5

Solution

In CrO5, the oxidation state of Cr can be calculated by assigning -2 to oxygen and solving for Cr. The structure has one Cr atom and five oxygen atoms, with two peroxides contributing a total charge of -4. The oxidation state of Cr is +5.

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