H2 -> 2H+ + 2e-. Calculate E°H2/H+ for E° = +0.59 V.

E°H2/H+ = 0.059 log (10^-10)^2/1
E°H2/H+ = +0.59 V
E°H2/H+ = 0.059 log 1/(10^-10)^2
None of the above

Correct answer: E°H2/H+ = +0.59 V

Solution

The standard electrode potential (E°) for the hydrogen electrode (H2/H+) is defined as 0.00 V under standard conditions. However, the question provides E° = +0.59 V, which directly matches option B.

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