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In weak alkaline medium, the equation is:

1. 2MnSO4 + H2O + I^- → 2MnO2 + IO4^- + 2OH^-
2. No. of molecules in different cases: 22.4 litre at STP contains 6.023 × 10^23 molecules of H2
3. 15 litre at STP contains 15/22.4 × 6.023 × 10^23
4. Similarly, 10 g of O2 contains 10/32 × 6.023 × 10^23 molecules

Correct answer: 2MnSO4 + H2O + I^- → 2MnO2 + IO4^- + 2OH^-

Solution

The reaction in option A represents a redox reaction in a weak alkaline medium, where MnSO4 is oxidized to MnO2 and I^- is oxidized to IO4^-.

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