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The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is:

1. one
2. two
3. five
4. one fifth

Correct answer: five

Solution

In an alkaline medium, KMnO4 is reduced to MnO2, and the oxidation state of Mn changes from +7 to +4. This involves a transfer of 3 electrons per Mn atom. KI acts as a reducing agent, and one mole of KI provides 2 moles of electrons. Therefore, 5 moles of KI are required to reduce 1 mole of KMnO4, making the number of moles of KMnO4 reduced by one mole of KI equal to 1/5.

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