Number of moles of MnO4^- required to oxidize one mole of ferrous oxalate completely in acidic medium will be:

6 moles
0.4 moles
7.5 moles
0.2 moles

Correct answer: 0.2 moles

Solution

In acidic medium, MnO4⁻ is reduced to Mn²⁺, and ferrous oxalate (FeC2O4) is oxidized. The balanced reaction shows that 1 mole of MnO4⁻ oxidizes 5 moles of Fe²⁺ and 2 moles of C2O4²⁻. Thus, 1 mole of ferrous oxalate requires 0.2 moles of MnO4⁻.

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