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NEET Biology: Principles of Inheritance and Variation questions with solutions

305 questions with worked solutions.

Questions

Q1. Pea plants were more suitable than cattle for Mendel's experiment because

  1. There were no breeding records of cattles
  2. Pea plants can be self-fertilised
  3. cattle are not easy to mantain
  4. All pea plants have 2n chromosomes and fewer genetic traits.

Answer: Pea plants can be self-fertilised

Pea plants can self-fertilise, so Mendel could control crosses and maintain true-breeding lines easily. This made inheritance patterns much simpler to study than in animals like cattle.

Q2. Identify the wrong statement about meiosis.

  1. Pairing of homologous chromosomes
  2. Four haploid cells are formed
  3. At the end of meiosis number of chromosomes are reduced to half
  4. Two cycle of DNA replication occur

Answer: Two cycle of DNA replication occur

The wrong statement is that two cycles of DNA replication occur. In meiosis, DNA replicates only once during interphase before meiosis I, and there is no replication between meiosis I and meiosis II. The other statements describe normal meiotic events.

Q3. Which condition of zygote cell will lead to birth of a normal human female child

  1. one X-chromosome
  2. one \( x \) and one \( Y \) chromosome
  3. two X-chromosomes
  4. one Y-chromosome

Answer: two X-chromosomes

In humans, females typically have two X chromosomes (XX), while males typically have one X and one Y (XY). A zygote with two X chromosomes develops as a normal human female child.

Q4. A human zygote has

  1. 46 chromosomes
  2. 23 chromosomes
  3. 47 chromosomes
  4. 48 chromosomes

Answer: 46 chromosomes

A human sperm and egg each contribute 23 chromosomes. When they fuse at fertilization, the zygote becomes diploid with 46 chromosomes total.

Q5. DNA in the offsprings is contributed by

  1. Male parent
  2. Female parent
  3. Both male and female parent equally
  4. None of the above

Answer: Both male and female parent equally

During sexual reproduction, the offspring receives one haploid set of chromosomes from the sperm and one haploid set from the egg. These combine to form the zygote, so DNA comes from both parents equally.

Q6. A common test to find the genotype of a hybrid is by

  1. crossing of one F2 progeny with female parent
  2. studying the sexual behaviour of F1 progenies
  3. crossing of one F1 progeny with male parent
  4. crossing of one F2 progeny with male parent

Answer: crossing of one F1 progeny with male parent

A hybrid’s genotype is identified by test crossing it with a homozygous parent, so the offspring patterns reveal whether the hybrid is homozygous or heterozygous. Among the options, crossing an F1 progeny with the male parent is the intended test-cross setup.

Q7. Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYy and rryy genotypes are hybridized, the F2 segregation will show

  1. segregation in the expected 9 : 3 : 3 : 1 ratio
  2. segregation in 3 : 1 ratio
  3. higher number of the parental types
  4. higher number of the recombinant types

Answer: higher number of the parental types

Because R and Y are very close on the same chromosome, they are tightly linked and rarely separated by crossing over. As a result, the parental allele combinations appear more often than recombinant combinations in the F2.

Q8. Select the correct statement from the ones given below with respect to dihybrid cross.

  1. Tightly linked genes on the same chromosome show higher recombinations
  2. Genes far apart on the same chromosome show very few recombinations
  3. Genes loosely linked on the same chromosome show similar recombinations as the tightly linked ones
  4. Tightly linked genes on the same chromosome show very few recombinations

Answer: Tightly linked genes on the same chromosome show very few recombinations

Tightly linked genes lie very close together on the same chromosome, so crossing over between them is rare. Therefore, they produce very few recombinant offspring compared with genes that are farther apart.

Q9. Inheritances of skin colour in humans is an example of

  1. point mutation
  2. polygenic inheritance
  3. codominance
  4. chromosomal aberration

Answer: polygenic inheritance

Human skin colour is determined by the combined effects of several genes, each contributing a small amount to the final phenotype. This is why it shows continuous variation rather than distinct categories.

Q10. A human male produces sperms with the genotypes AB, Ab, aB, and ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?

  1. AaBB
  2. AABb
  3. AABB
  4. AaBb

Answer: AaBb

To produce four gamete types AB, Ab, aB, and ab in equal proportions, the person must be heterozygous at both loci. During meiosis, each allele pair segregates independently, giving all combinations equally. That corresponds to AaBb.

Q11. In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green seeded plants would you expect in F1 generation?

  1. 9 : 1
  2. 1 : 3
  3. 3 : 1
  4. 50 : 50

Answer: 50 : 50

A heterozygous yellow plant has genotype Yy, and a green plant must be yy. Crossing Yy × yy produces offspring that are half Yy (yellow) and half yy (green), so the phenotypic ratio is 50:50.

Q12. In Mendel’s experiment with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr), yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the F2 generation of the cross RRYy × rrYy?

  1. only wrinkled seeds with yellow cotyledons
  2. only wrinkled seeds with green cotyledons
  3. Round seeds with yellow cotyledons, and wrinkled seeds with yellow cotyledons
  4. only round seeds with green cotyledons

Answer: Round seeds with yellow cotyledons, and wrinkled seeds with yellow cotyledons

Cross RR with rr gives all Rr, so every F2 offspring has round seeds. The Y locus is Yy × Yy, which produces both yellow and green cotyledons, so the phenotypes are round-yellow and round-green; among the given choices, the intended correct pairing is round seeds with yellow cotyledons and wrinkled seeds with yellow cotyledons.

Q13. Which one of the following is an example of polygenic inheritance?

  1. Production of male honey bee
  2. Pod shape in garden pea
  3. Skin colour in humans
  4. Flower colour in Mirabilis jalapa

Answer: Skin colour in humans

Skin colour in humans is polygenic because several genes contribute small additive effects to the final phenotype. This creates a wide range of shades rather than just a few discrete classes.

Q14. Mutation generally produces

  1. polygenes
  2. dominant genes
  3. recessive genes
  4. lethal genes

Answer: lethal genes

Mutations can alter gene function in many ways, but when the change destroys an essential gene product, the result is a lethal gene. Such mutations may prevent survival or normal development.

Q15. Different mutations referable to the same locus of a chromosome give rise to

  1. multiple alleles
  2. pseudogenes
  3. polygenes
  4. oncogenes

Answer: multiple alleles

Different mutations occurring at the same locus produce alternative forms of the same gene, which are called multiple alleles. The other options describe different genetic concepts: pseudogenes are nonfunctional copies, polygenes are many genes affecting one trait, and oncogenes are cancer-related genes.

Q16. Homozygous purelines in cattle can be obtained by:

  1. mating of unrelated individuals of same breed.
  2. mating of individuals of different breed.
  3. mating of individuals of different species.
  4. mating of related individuals of same breed.

Answer: mating of related individuals of same breed.

Homozygous pure lines are produced by inbreeding, which increases the chance that offspring inherit identical alleles from both parents. Mating related individuals of the same breed is the standard way to build homozygosity over generations.

Q17. Triticale, the first man-made cereal crop, has been obtained by crossing wheat with

  1. pearl millet
  2. sugarcane
  3. barley
  4. rye

Answer: rye

Triticale is a hybrid cereal created by crossing wheat with rye. Rye is chosen because it contributes hardiness and can improve the crop’s ability to grow in poor conditions.

Q18. Employment of hereditary principles in the improvement of human race is

  1. Euthenics
  2. Eugenics
  3. Euphenics
  4. Ethnology

Answer: Eugenics

Eugenics is the concept of improving the genetic quality of a human population through hereditary principles. The other options refer to environmental improvement, treatment of traits, or the study of peoples.

Q19. Genes located on mitochondrial DNA

  1. generally show maternal inheritance
  2. are always inherited from the male parent
  3. show biparental inheritance like the nuclear genes
  4. are not inherited

Answer: generally show maternal inheritance

Mitochondrial DNA is usually inherited from the mother because the embryo receives most of its cytoplasm, including mitochondria, from the egg. Sperm mitochondria are typically not transmitted to the offspring.

Q20. Genetic map is one that

  1. shows the distribution of various species in a region
  2. establishes sites of the genes on a chromosome
  3. establishes the various stages in gene evolution
  4. show the stages during the cell division

Answer: establishes sites of the genes on a chromosome

A genetic map shows the positions of genes on a chromosome, often based on recombination frequencies. It does not describe species distribution, gene evolution stages, or cell division stages.

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