Exams › JEE Main › Maths
A binomial distribution has mean 4 and variance 2. Find the probability of exactly 2 successes.
- 128/256
- 219/256
- 37/256
- 28/256
Correct answer: 28/256
Solution
From np = 4 and npq = 2 we get q = 1/2, p = 1/2, n = 8; then P(X=2) = C(8,2)(1/2)⁸ = 28/256.
Related JEE Main Maths questions
- A random variable can assume the values 0, 1, 2,..., n, and its corresponding frequencies are proportional to the coefficients nC0, nC1, nC2,..., nCn. What is the variance of this distribution?
- From the integers 1, 2, 3,..., 2004, two distinct numbers x and y are selected at random without replacement. What is the probability that x³ + y³ is divisible by 3?
- One card is selected at random from a standard deck of 52 cards. A player wagers that the card will be a spade or an ace. What are the odds against the player winning the wager?
- When n objects are assigned randomly to n people, what is the probability that at least one person receives no object?
- For two arbitrary events M and N, what is the probability that one and only one of them happens?
- A four-digit number is made using the digits 1, 2, 3, and 4 without repeating any digit. What is the probability that the resulting number is odd?
⚔️ Practice JEE Main Maths free + battle 1v1 →