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A four-digit number is made using the digits 1, 2, 3, and 4 without repeating any digit. What is the probability that the resulting number is odd?
- 0
- 1/3
- 1/4
- None of these
Correct answer: None of these
Solution
Among the four digits two are odd (1,3) and two even (2,4). The last digit is equally likely to be any of the four, so P(odd) = 2/4 = 1/2, which is not listed; the answer is None of these.
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