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A random variable can assume the values 0, 1, 2,..., n, and its corresponding frequencies are proportional to the coefficients nC0, nC1, nC2,..., nCn. What is the variance of this distribution?
- n/4
- n/3
- 2n/5
- None of these
Correct answer: n/4
Solution
Frequencies proportional to nC0,nC1,...,nCn give a binomial distribution with p=1/2. Variance = n·p·(1-p) = n·(1/2)·(1/2) = n/4.
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