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A random variable X has the following probability distribution : X : 1 2 3 4 5 P(X) : K^2 2K K 2K 5K^2 Then P(X > 2) is equal to -

1. 1/36
2. 1/6
3. 7/12
4. 23/36

Correct answer: 23/36

Solution

To find P(X > 2), we sum the probabilities for X = 3, 4, and 5. The total probability is calculated as P(X=3) + P(X=4) + P(X=5) = K + 2K + 5K^2. After determining K from the normalization condition of the probability distribution, we find that P(X > 2) equals 23/36.

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