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Two numbers x and y are independently selected with replacement from the set {0, 1, 2, 3,..., 10}. What is the probability that the absolute difference between them exceeds 5?
- 81/121
- 30/121
- 25/121
- 20/121
Correct answer: 30/121
Solution
Total ordered pairs = 11x11 = 121. For |x-y|=d (d=6..10) there are 2(11-d) ordered pairs: 10+8+6+4+2 = 30. Probability = 30/121.
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