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In a leap year, what is the probability that the year contains 53 Fridays or 53 Saturdays?

1. 2/7
2. 3/7
3. 4/7
4. 1/7

Correct answer: 3/7

Solution

A leap year has 366 = 52 weeks + 2 extra consecutive days. P(53 Fri) = 2/7, P(53 Sat) = 2/7, and P(both, i.e. extra days are Fri&Sat) = 1/7. So P = 2/7 + 2/7 - 1/7 = 3/7.

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