Exams › JEE Main › Chemistry

For the reaction 2SO2 + O2 ⇌ 2SO3, K = 278 (given). Calculate K' for the reaction SO3 ⇌ SO2 + 1/2 O2.

1. 1 / √278
2. 6 × 10^-2
3. √278
4. 1 / K

Correct answer: 1 / K

Solution

To find K' for the reaction SO3 ⇌ SO2 + 1/2 O2, we need to reverse the original reaction and change the sign of K.

Related JEE Main Chemistry questions

• For the gaseous reaction \(\mathrm{CO(g) + \tfrac{1}{2}O_2(g) \rightleftharpoons CO_2(g)}\), what is the relation between \(K_p\) and \(K_c\)?
• For the gaseous equilibrium \(\mathrm{PCl_5 \rightleftharpoons PCl_3 + Cl_2}\), how does the degree of dissociation \((\alpha)\) depend on the equilibrium pressure \((p)\)?
• A movable-piston vessel of volume 20 L at 400 K contains \(\mathrm{CO_2(g)}\) at a pressure of 0.4 atm along with excess \(\mathrm{SrO}\) (ignore the solid’s volume). The piston is pushed inward, reducing the container volume. What is the largest volume the vessel can have when the \(\mathrm{CO_2}\) pressure reaches its highest value?\n\nGiven: \(\mathrm{SrCO_3(s) \rightleftharpoons SrO(s) + CO_2(g)}\), \(K_p = 1.6\) atm
• For the equilibrium \(\mathrm{C(s) + CO_2(g) \rightleftharpoons 2CO(g)}\), the value of \(K_p\) is 63 atm at 1000 K. If, at equilibrium, the partial pressure of \(\mathrm{CO}\) is ten times the partial pressure of \(\mathrm{CO_2}\), what is the total pressure of the gaseous mixture at equilibrium?
• Which of the following sequences lists the substances in order of increasing solubility?
• Which of the following statements is incorrect?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →