Exams › JEE Main › Chemistry
The pair of species that has the same bond order in the following is:
- O2, B2
- CO, NO+
- NO+, CN−
- O2, N2
Correct answer: O2, N2
Solution
Both O2 and N2 have a bond order of 2.5, which is the same.
Related JEE Main Chemistry questions
- Although the electronegativity gap between N and F is larger than that between N and H, ammonia has a dipole moment of 1.5 D while nitrogen trifluoride has only 0.2 D. The reason is that
- When N₂ is converted into N₂⁺, the dissociation energy of the N–N bond ______, and when O₂ is converted into O₂⁺, the dissociation energy of the O–O bond ______.
- Using molecular orbital theory, which sequence arranges the nitrogen species in order of increasing bond order?
- From the ions listed below, which pair has geometries that can be accounted for by the same type of orbital hybridization? NO₂⁻, NO₃⁻, NH₂⁻, NH₄⁺, SCN⁻
- Atoms A and B have electronegativities of 1.20 and 4.0, respectively. What is the percentage ionic character of the A–B bond?
- In the phosphate ion, \(\mathrm{PO_4^{3-}}\), what is the formal charge on an oxygen atom that is singly bonded to phosphorus?
⚔️ Practice JEE Main Chemistry free + battle 1v1 →