Exams › JEE Main › Chemistry

The correct order of acidic strength of the major products formed in the given reactions, is : A. PhNH2 (1) NaNO2 + HCl (5°C) (2) CuCN (3) H3O+/Δ → [A] B. CH3CH2CHO [Ag(NH3)2]+, OH−, Δ → [B] C. CH4 + O2 (i) Mo2O3 (ii) Na2Cr2O7/H+ → [C] D. PhCH2MgBr + CO2 Dry ether, H3O+ → [D] Choose the correct answer from the options given below :

1. C > B > A > D
2. A > D > C > B
3. A > D > B > C
4. C > A > D > B

Correct answer: C > A > D > B

Solution

The order of acidic strength is determined by the stability of the conjugate bases formed after deprotonation. In this case, the products from the reactions show that the conjugate base from C is the most stable due to resonance, followed by A, which has a stable aromatic system, then D, which is less stable, and finally B, which is the least acidic due to the presence of an aldehyde.

Related JEE Main Chemistry questions

• When benzil (PhCOCOPh) is reduced using LiAlH4, how many asymmetric carbon atoms are formed, and how many stereoisomers can result?
• What is the product formed when toluene (C6H5CH3) is treated with chromyl chloride (CrO2Cl2)?
• o-Xylene is first treated with HNO3 to give compound X, which on reaction with phenol in the presence of H2SO4 forms product Y. What is Y?
• What products are formed when a benzene ring containing a formyl group (–CHO) and a chloro substituent is treated with 50% KOH?
• Which of the following compounds contains a carboxyl group (–COOH)?
• Which of the following compounds is converted to the corresponding hydrocarbon on reduction with zinc and hydrochloric acid?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →