Exams › JEE Main › Chemistry

Match List I with List II. LIST I (Molecule/Species) A. SO2Cl2 B. NO C. NO2− D. I3− LIST II (Property/Shape) I. Paramagnetic II. Diamagnetic III. Tetrahedral IV. Linear Choose the correct answer from the options given below:

1. A-IV, B-I, C-III, D-II
2. A-III, B-I, C-II, D-IV
3. A-II, B-III, C-I, D-IV
4. A-III, B-IV, C-II, D-I

Correct answer: A-III, B-I, C-II, D-IV

Solution

The correct option matches the molecular shapes and magnetic properties accurately: SO2Cl2 has a tetrahedral shape (III), NO is paramagnetic due to its unpaired electron (I), NO2− is diamagnetic as all its electrons are paired (II), and I3− has a linear shape (IV).

Related JEE Main Chemistry questions

• Although the electronegativity gap between N and F is larger than that between N and H, ammonia has a dipole moment of 1.5 D while nitrogen trifluoride has only 0.2 D. The reason is that
• When N₂ is converted into N₂⁺, the dissociation energy of the N–N bond ______, and when O₂ is converted into O₂⁺, the dissociation energy of the O–O bond ______.
• Using molecular orbital theory, which sequence arranges the nitrogen species in order of increasing bond order?
• From the ions listed below, which pair has geometries that can be accounted for by the same type of orbital hybridization? NO₂⁻, NO₃⁻, NH₂⁻, NH₄⁺, SCN⁻
• Atoms A and B have electronegativities of 1.20 and 4.0, respectively. What is the percentage ionic character of the A–B bond?
• In the phosphate ion, \(\mathrm{PO_4^{3-}}\), what is the formal charge on an oxygen atom that is singly bonded to phosphorus?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →