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A solution of two miscible liquids showing negative deviation from Raoult’s law will have : (1) increased vapour pressure, decreased boiling point (2) increased vapour pressure, increased boiling point (3) decreased vapour pressure, decreased boiling point (4) decreased vapour pressure, increased boiling point
- increased vapour pressure, decreased boiling point
- increased vapour pressure, increased boiling point
- decreased vapour pressure, decreased boiling point
- decreased vapour pressure, increased boiling point
Correct answer: decreased vapour pressure, increased boiling point
Solution
A negative deviation from Raoult's law indicates that the interactions between the molecules of the two liquids are stronger than those between the molecules of each liquid alone, leading to a lower vapor pressure and a higher boiling point compared to what would be expected if the liquids behaved ideally.
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