StreakPeaked· Practice

ExamsJEE MainChemistry

A solution of two miscible liquids showing negative deviation from Raoult’s law will have : (1) increased vapour pressure, decreased boiling point (2) increased vapour pressure, increased boiling point (3) decreased vapour pressure, decreased boiling point (4) decreased vapour pressure, increased boiling point

  1. increased vapour pressure, decreased boiling point
  2. increased vapour pressure, increased boiling point
  3. decreased vapour pressure, decreased boiling point
  4. decreased vapour pressure, increased boiling point

Correct answer: decreased vapour pressure, increased boiling point

Solution

A negative deviation from Raoult's law indicates that the interactions between the molecules of the two liquids are stronger than those between the molecules of each liquid alone, leading to a lower vapor pressure and a higher boiling point compared to what would be expected if the liquids behaved ideally.

Related JEE Main Chemistry questions

⚔️ Practice JEE Main Chemistry free + battle 1v1 →