Exams › JEE Main › Chemistry
Car radiators use an aqueous ethylene glycol solution as antifreeze. How much ethylene glycol should be mixed with 5 kg of water so that the freezing point is lowered to -0.3 °C? (K_f = 1.86 K kg mol⁻¹)
- 50 kg
- 50 g
- 45 g
- 40 g
Correct answer: 50 g
Solution
The correct option is 50 g because to achieve a freezing point depression of -0.3 °C, the calculated amount of ethylene glycol needed, based on the freezing point depression formula, is approximately 50 g when mixed with 5 kg of water.
Related JEE Main Chemistry questions
⚔️ Practice JEE Main Chemistry free + battle 1v1 →