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ExamsJEE MainChemistry

Match List-I with List-II List-I (A) ΨMO = ΨA − ΨB (B) μ = Q × r (C) (N_b − N_a)/2 (D) ΨMO = ΨA + ΨB List-II (I) Dipole moment (II) Bonding molecular orbital (III) Anti-bonding molecular orbital (IV) Bond order Choose the correct answer from options given below :

  1. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  2. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  3. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  4. (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Correct answer: (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Solution

The correct option matches the equations and concepts accurately: ΨMO = ΨA − ΨB describes the formation of an anti-bonding molecular orbital, μ = Q × r defines the dipole moment, (N_b − N_a)/2 calculates the bond order, and ΨMO = ΨA + ΨB represents a bonding molecular orbital.

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