Exams › JEE Main › Chemistry

Which reactant will give the following alcohol on reaction with one mole of phenyl magnesium bromide (PhMgBr) followed by acidic hydrolysis? Target alcohol: Ph2C(OH)CH3

1. CH3 – C ≡ N
2. Ph – C ≡ N
3. CH3 – C(=O) – O – Ph
4. Ph – C(=O) – CH3

Correct answer: Ph – C(=O) – CH3

Solution

The correct option, Ph – C(=O) – CH3, contains a carbonyl group that can react with phenyl magnesium bromide to form a tertiary alcohol after the addition of the Grignard reagent and subsequent acidic hydrolysis, resulting in the target alcohol structure.

Related JEE Main Chemistry questions

• When benzil (PhCOCOPh) is reduced using LiAlH4, how many asymmetric carbon atoms are formed, and how many stereoisomers can result?
• What is the product formed when toluene (C6H5CH3) is treated with chromyl chloride (CrO2Cl2)?
• o-Xylene is first treated with HNO3 to give compound X, which on reaction with phenol in the presence of H2SO4 forms product Y. What is Y?
• What products are formed when a benzene ring containing a formyl group (–CHO) and a chloro substituent is treated with 50% KOH?
• Which of the following compounds contains a carboxyl group (–COOH)?
• Which of the following compounds is converted to the corresponding hydrocarbon on reduction with zinc and hydrochloric acid?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →