Exams › JEE Main › Chemistry
Among the following species N2, N2+, N2-, N2^2-, O2, O2+, O2-, O2^2- the number of species showing diamagnetism is _________.
- 1
- 2
- 3
- 4
Correct answer: 1
Solution
Diamagnetic species have all their electrons paired, which means they do not have any unpaired electrons. Among the given species, only N2 is diamagnetic, while the others contain unpaired electrons, making them paramagnetic.
Related JEE Main Chemistry questions
- Although the electronegativity gap between N and F is larger than that between N and H, ammonia has a dipole moment of 1.5 D while nitrogen trifluoride has only 0.2 D. The reason is that
- When N₂ is converted into N₂⁺, the dissociation energy of the N–N bond ______, and when O₂ is converted into O₂⁺, the dissociation energy of the O–O bond ______.
- Using molecular orbital theory, which sequence arranges the nitrogen species in order of increasing bond order?
- From the ions listed below, which pair has geometries that can be accounted for by the same type of orbital hybridization? NO₂⁻, NO₃⁻, NH₂⁻, NH₄⁺, SCN⁻
- Atoms A and B have electronegativities of 1.20 and 4.0, respectively. What is the percentage ionic character of the A–B bond?
- In the phosphate ion, \(\mathrm{PO_4^{3-}}\), what is the formal charge on an oxygen atom that is singly bonded to phosphorus?
⚔️ Practice JEE Main Chemistry free + battle 1v1 →