Exams › JEE Main › Chemistry

The correct match between Item-I (starting material) and Item-II (reagent) for the preparation of benzaldehyde is: Item-I: (I) Benzene, (II) Benzonitrile, (III) Benzoyl Chloride Item-II: (P) HCl and SnCl2, H3O+, (Q) H2, Pd-BaSO4, S and quinoline, (R) CO, HCl and AlCl3

1. (I)-(Q), (II)-(R) and (III)-(P)
2. (I)-(R), (II)-(Q) and (III)-(P)
3. (I)-(P), (II)-(Q) and (III)-(R)
4. (I)-(P), (II)-(Q) and (III)-(R)

Correct answer: (I)-(R), (II)-(Q) and (III)-(P)

Solution

The correct matches are based on the specific reactions required to convert each starting material into benzaldehyde. Benzene reacts with carbon monoxide and hydrochloric acid in the presence of aluminum chloride to form benzaldehyde, while benzonitrile is reduced using hydrogen and palladium on barium sulfate to yield benzaldehyde, and benzoyl chloride undergoes hydrolysis with hydrochloric acid and tin(II) chloride to produce benzaldehyde.

Related JEE Main Chemistry questions

• When benzil (PhCOCOPh) is reduced using LiAlH4, how many asymmetric carbon atoms are formed, and how many stereoisomers can result?
• What is the product formed when toluene (C6H5CH3) is treated with chromyl chloride (CrO2Cl2)?
• o-Xylene is first treated with HNO3 to give compound X, which on reaction with phenol in the presence of H2SO4 forms product Y. What is Y?
• What products are formed when a benzene ring containing a formyl group (–CHO) and a chloro substituent is treated with 50% KOH?
• Which of the following compounds contains a carboxyl group (–COOH)?
• Which of the following compounds is converted to the corresponding hydrocarbon on reduction with zinc and hydrochloric acid?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →