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(I) H – N --- N --- N (II) In hydrogen azide, the bond orders of bonds (I) and (II) are _____.

1. (I) 2, II>2
2. (I) >2, II>2
3. (I) >2, II<2
4. (I) <2, II<2

Correct answer: (I) 2, II>2

Solution

In hydrogen azide, the bond order of the nitrogen-nitrogen bond (I) is 2 due to the presence of a double bond, while the bond order of the terminal nitrogen-nitrogen bond (II) is greater than 2 because it involves resonance structures that contribute to a higher effective bond order.

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