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ExamsJEE MainChemistry

Match each compound in List-I with the reaction/product in List-II and choose the correct code. List I (A) Benzaldehyde (B) Phthalic anhydride (C) Phenyl benzoate (D) Methyl salicylate List II (i) Phenolphthalein (ii) Benzoin condensation (iii) Oil of wintergreen (iv) Fries rearrangement

  1. (A)-(iv), (B)-(i), (C)-(iii), (D)-(ii)
  2. (A)-(iv), (B)-(i), (C)-(ii), (D)-(iii)
  3. (A)-(ii), (B)-(iii), (C)-(iv), (D)-(i)
  4. (A)-(ii), (B)-(iv), (C)-(iii), (D)-(i)

Correct answer: (A)-(iv), (B)-(i), (C)-(ii), (D)-(iii)

Solution

The correct matches are based on the specific reactions or products associated with each compound: Benzaldehyde undergoes the Fries rearrangement, Phthalic anhydride is used to synthesize phenolphthalein, Phenyl benzoate is involved in benzoin condensation, and Methyl salicylate is known as oil of wintergreen.

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