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The compound A in the following reactions is: A (i) CH3MgBr/H2O (ii) Conc. H2SO4/Δ → B (i) O2 (ii) Zn/H2O → C + D C (i) Conc. KOH (ii) Δ → C6H5COO−K+ + C6H5CH2OH D Ba(OH)2 Δ → CH3–C(CH3)=CH–CO–CH3

1. (1) C6H5–CO–CH(CH3)2
2. (2) C6H5–CH2–CO–CH3
3. (3) C6H5–CO–CH2CH3
4. (4) C6H5–CO–CH3

Correct answer: (2) C6H5–CH2–CO–CH3

Solution

The correct option is C6H5–CH2–CO–CH3 because the reactions indicate that compound A undergoes a Grignard reaction followed by acid hydrolysis, leading to the formation of a benzyl alcohol and a ketone, which aligns with the structure of option (2).

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