Exams › JEE Main › Chemistry

In the reaction CH3COOH —LiAlH4→ A —PCl5→ B —Alc. KOH→ C the product C is -

1. Acetylene
2. Ethylene
3. Acetyl chloride
4. Acetaldehyde

Correct answer: Ethylene

Solution

The reaction sequence involves the reduction of acetic acid (CH3COOH) to ethanol, which is then dehydrated by PCl5 to form an alkene. The presence of alcoholic KOH facilitates the elimination of water, resulting in the formation of ethylene.

Related JEE Main Chemistry questions

• What is the product formed when toluene (C6H5CH3) is treated with chromyl chloride (CrO2Cl2)?
• o-Xylene is first treated with HNO3 to give compound X, which on reaction with phenol in the presence of H2SO4 forms product Y. What is Y?
• What products are formed when a benzene ring containing a formyl group (–CHO) and a chloro substituent is treated with 50% KOH?
• Which of the following compounds contains a carboxyl group (–COOH)?
• Which of the following compounds is converted to the corresponding hydrocarbon on reduction with zinc and hydrochloric acid?
• Why do carboxylic acids not undergo the typical addition–elimination reactions shown by aldehydes and ketones?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →