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In the sequence of reactions, CH3COOH —LiAlH4→ A A —PCl5→ B B —alcoholic KOH→ C, what is the compound C?

1. Acetaldehyde
2. Acetylene
3. Ethene
4. Acetyl chloride

Correct answer: Ethene

Solution

The sequence starts with acetic acid (CH3COOH) being reduced by LiAlH4 to form ethanol (A). When ethanol reacts with PCl5, it forms ethyl chloride (B), which upon treatment with alcoholic KOH undergoes elimination to produce ethene (C).

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