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In Cannizzaro reaction given below 2PhCHO —OH−→ PhCH2OH + PhCO2− the slowest step is:

1. the transfer of hydride to the carbonyl group
2. the abstraction of proton from the carboxylic group
3. the deprotonation of Ph CH2OH
4. the attack of:OH− at the carboxyl group

Correct answer: the transfer of hydride to the carbonyl group

Solution

The transfer of hydride to the carbonyl group is the slowest step because it involves the formation of a new bond and is typically the rate-determining step in reactions involving nucleophilic addition to carbonyl compounds.

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