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The tetrahedral intermediate shown below collapses to form: CH3—CH2—C(OH)(OCH3)—Cl

1. propanal and HCl
2. methyl propanoate and HCl
3. propanoic acid and CH3Cl
4. propyl chloride and CH3OH

Correct answer: methyl propanoate and HCl

Solution

The tetrahedral intermediate undergoes a rearrangement where the hydroxyl group is converted into a methoxy group, leading to the formation of methyl propanoate, while releasing HCl as a byproduct.

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