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Two neighbouring coils have a mutual inductance of 1.5 H. If the current in one coil rises from 0 to 20 A in 0.5 s, what is the change in the flux linkage of the other coil?

1. 30 Wb
2. 15 Wb
3. 60 Wb
4. 10 Wb

Correct answer: 30 Wb

Solution

The flux linkage of the second coil is N*phi = M*I. The change is delta(N*phi) = M*delta(I) = 1.5 * (20 - 0) = 30 Wb. The 0.5 s interval is needed only if the induced EMF were asked.

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