Exams › JEE Advanced › Physics
Determine the inductance per unit length for a loop created by connecting the ends of two infinitely long parallel wires, each with radius r, and separated by a distance d between their centers. Ignore the magnetic flux inside the wires and the effects at the ends.
- μ₀ / (2π) * logₑ((d − r) / r)
- μ₀ / (2π) * logₑ((d + r) / r)
- μ₀ / π * logₑ((d − r) / r)
- None of the above
Correct answer: μ₀ / π * logₑ((d − r) / r)
Solution
The inductance per unit length for the loop is derived by considering the magnetic flux outside the wires and the separation distance. The correct formula is μ₀ / π * logₑ((d − r) / r).
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →