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If the electromotive force is 10 V and the rate of change of current is calculated as 2.5 A/s, what is the self-inductance of the coil, given by L = e / (dl/dt)?

1. 4 H
2. 2 H
3. 6 H
4. 8 H

Correct answer: 4 H

Solution

The self-inductance is calculated using L = e / (di/dt). Substituting the given values, L = 10 V / 2.5 A/s = 4 H.

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