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A current of 2 A is increasing at the rate of 4 A/s through a coil of inductance 2 H. The rate at which energy is being stored in the inductor (energy per unit time) is:

1. 2 J/s
2. 1 J/s
3. 16 J/s
4. 4 J/s

Correct answer: 16 J/s

Solution

U = (1/2)*L*I², so dU/dt = L*I*(dI/dt) = 2 * 2 * 4 = 16 J/s.

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