Exams › JEE Advanced › Physics

A thin conducting circular loop of area 3.5 * 10⁻³ m² and resistance 10 ohm is placed perpendicular to a uniform time-varying magnetic field B(t) = (0.4 T) sin(50*pi*t). Find the net charge that flows through the loop between t = 0 and t = 10 ms.

1. 0.14 mC
2. 0.21 mC
3. 0.06 mC
4. 0.07 mC

Correct answer: 0.14 mC

Solution

Charge is the change in flux divided by resistance. B goes from 0 (t=0) to 0.4 T (t=10 ms, since sin(pi/2)=1). delta(flux) = A*delta(B) = 3.5e-3 * 0.4 = 1.4e-3 Wb. q = 1.4e-3/10 = 1.4e-4 C = 0.14 mC.

Related JEE Advanced Physics questions

• What is the final velocity attained by the loop?
• A long coaxial cable is made up of two cylindrical conductors with radii a and b. The inner conductor carries a constant current i, while the outer conductor acts as the return path for the current. What is the self-inductance of a segment of the cable of length l?
• Determine the inductance per unit length for a loop created by connecting the ends of two infinitely long parallel wires, each with radius r, and separated by a distance d between their centers. Ignore the magnetic flux inside the wires and the effects at the ends.
• If the electromotive force is 10 V and the rate of change of current is calculated as 2.5 A/s, what is the self-inductance of the coil, given by L = e / (dl/dt)?
• The magnitude of the induced electric field in the orbit at any instant of time during the time interval of the magnetic field change is
• A semicircular loop of radius r is positioned on the axis of a large current-carrying circular ring of radius R (with R >> r). The loop is placed at an axial distance of R*sqrt(3) from the center of the ring, and the plane of the semicircular loop makes an angle of 53 deg with the plane of the ring. Find the mutual inductance M between the two coils.

⚔️ Practice JEE Advanced Physics free + battle 1v1 →