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A capacitor of capacitance 2 microF is charged to a potential difference of 12 V. It is then connected across an inductor of inductance 0.6 mH. At the instant when the potential difference across the capacitor is 6.0 V, the current in the circuit is x amperes. Find the value of 10x.

1. 1
2. 2
3. 3
4. 4

Correct answer: 3

Solution

In an LC circuit, total electromagnetic energy is conserved. Initially all energy is in the capacitor. When voltage drops to 6 V, part of the energy has transferred to the inductor. Setting up the energy equation gives the current, and 10x = 3.

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