Exams › JEE Advanced › Physics
Correct answer: 2
For a coil rotating in a magnetic field: EMF = N * B * A * omega * sin(omega*t), where A = pi * R² is the area. The maximum (amplitude) of EMF is epsilon_max = N * B * pi * R² * omega. The amplitude of current = epsilon_max / eta = N * B * pi * R² * omega / eta. The given expression for amplitude is P * (N * B * omega * pi * R²) / (2*eta). Setting equal: N*B*pi*R²*omega / eta = P * N*B*omega*pi*R² / (2*eta). Therefore P/2 = 1 => P = 2.