Exams › JEE Advanced › Physics

Assertion (A): Self-inductance is often referred to as the electromagnetic analogue of inertia (or electromagnetic inertia). Reason (R): Self-inductance is the property of a coil by which an opposing e.m.f. is induced in the coil whenever the current through it (and hence the magnetic flux linked with it) changes. Which of the following correctly describes the above statements?

1. Both A and R are correct, and R is the correct explanation of A.
2. Both A and R are correct, but R is not the correct explanation of A.
3. A is correct but R is incorrect.
4. A is incorrect but R is correct.

Correct answer: Both A and R are correct, and R is the correct explanation of A.

Solution

Self-inductance resists changes in current (e = -L*dI/dt), exactly analogous to how mechanical inertia resists changes in velocity (F = ma). The reason correctly describes this opposing nature, making it a valid explanation for why self-inductance is called electromagnetic inertia.

Related JEE Advanced Physics questions

• What is the final velocity attained by the loop?
• A long coaxial cable is made up of two cylindrical conductors with radii a and b. The inner conductor carries a constant current i, while the outer conductor acts as the return path for the current. What is the self-inductance of a segment of the cable of length l?
• Determine the inductance per unit length for a loop created by connecting the ends of two infinitely long parallel wires, each with radius r, and separated by a distance d between their centers. Ignore the magnetic flux inside the wires and the effects at the ends.
• If the electromotive force is 10 V and the rate of change of current is calculated as 2.5 A/s, what is the self-inductance of the coil, given by L = e / (dl/dt)?
• The magnitude of the induced electric field in the orbit at any instant of time during the time interval of the magnetic field change is
• A semicircular loop of radius r is positioned on the axis of a large current-carrying circular ring of radius R (with R >> r). The loop is placed at an axial distance of R*sqrt(3) from the center of the ring, and the plane of the semicircular loop makes an angle of 53 deg with the plane of the ring. Find the mutual inductance M between the two coils.

⚔️ Practice JEE Advanced Physics free + battle 1v1 →