Exams › JEE Advanced › Chemistry
Correct answer: 2 and 3
(a) CH3-C(=O)-CH2⁻ is an enolate. The carbanion lone pair conjugates with the C=O: one structure has the charge on carbon (C=O intact), the other has the charge on oxygen with a C=C formed. That is 2 contributing structures. (b) H-C(=O)-CH=CH-CH2⁻ is an extended/conjugated carbanion. The negative charge can stay on the terminal CH2, shift onto the internal carbon as the C=C migrates, and finally reach the carbonyl oxygen giving an alkoxide with the full conjugated chain. That gives 3 contributing structures. So the answers are 2 and 3.