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When two 1s atomic orbitals (one from each atom) combine to form molecular orbitals, which of the following statements is correct?
- The bonding molecular orbital (BMO) is formed by constructive overlap and has lower energy than the atomic orbitals
- The antibonding molecular orbital (ABMO) is formed by constructive overlap and has higher energy
- The gerade (symmetric) combination is given by: psi_g = psi_A + psi_B
- The ungerade (antisymmetric) combination is given by: psi_u = psi_A + psi_B
Correct answer: The gerade (symmetric) combination is given by: psi_g = psi_A + psi_B
Solution
The in-phase combination psi_A + psi_B produces the bonding sigma MO, which has gerade symmetry (symmetric under inversion through the bond centre), so psi_g = psi_A + psi_B. The out-of-phase combination psi_A - psi_B is ungerade and antibonding.
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