Exams › JEE Advanced › Chemistry

According to molecular orbital theory, what is the ratio of the number of pi electrons in C2 to that in B2?

1. 1:1
2. 2:1
3. 1:2
4. 3:2

Correct answer: 2:1

Solution

In B2 (6 valence-region electrons in this scheme) 2 electrons occupy pi(2p) orbitals, while in C2 all 4 bonding electrons occupy the pi(2p) orbitals, giving a pi-electron ratio of 4:2 = 2:1.

Related JEE Advanced Chemistry questions

• When N₂ is converted to N₂⁺, what happens to the bond dissociation energy of the N–N bond, and when O₂ is converted to O₂⁺, what happens to the bond dissociation energy of the O–O bond?
• In which of these ions is pπ–dπ bonding absent?
• What is the VSEPR formula for the chlorine trifluoride molecule?
• Consider the following molecules: CO2, SO2, and H2O. Arrange them in ascending order of their dipole moments.
• Which of the following occurrences is primarily influenced by hydrogen bonding?
• When two 1s atomic orbitals (one from each atom) combine to form molecular orbitals, which of the following statements is correct?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →