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ExamsJEE AdvancedChemistry

Match the type of ionic compound in List-I with the location of the cation in the unit cell in List-II. List-I: (P) NaCl type, (Q) ZnS (zinc blende) type, (R) CsCl type, (S) Na2O (antifluorite) type. List-II: (1) Cation at 50% of tetrahedral voids, (2) Cation at 100% of tetrahedral voids, (3) Cation at cubic void, (4) Cation at 100% of octahedral voids. Match P, Q, R, S with 1, 2, 3, 4.

  1. P-4, Q-1, R-3, S-2
  2. P-2, Q-1, R-4, S-1
  3. P-1, Q-2, R-3, S-4
  4. P-4, Q-3, R-4, S-2

Correct answer: P-4, Q-1, R-3, S-2

Solution

In NaCl structure, Na+ occupies all octahedral voids (100%) in the FCC arrangement of Cl- — matches List-II item 4. In zinc blende ZnS, Zn2+ occupies 50% of tetrahedral voids — matches item 1. In CsCl, Cs+ sits at the body-centre (cubic void) in a simple cubic arrangement of Cl- — matches item 3. In Na2O (antifluorite), Na+ occupies all (100%) tetrahedral voids with O2- in FCC — matches item 2. So P-4, Q-1, R-3, S-2.

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