Exams › JEE Advanced › Chemistry
Correct answer: sqrt(3)*a/4
In spinel structure (like Fe3O4 = FeO*Fe2O3), Fe2+ occupies tetrahedral voids and Fe3+ occupies octahedral voids (normal spinel). The minimum distance between a tetrahedral void and the nearest octahedral void in an FCC arrangement is sqrt(3)*a/4, where a is the unit cell parameter.