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For the cell Pt | H2 | HCl | AgCl | Ag, the EMF varies with temperature as E_cell = 0.4 - 2*10⁻⁶*T² V (T in Kelvin). Find delta G for the cell reaction (1/2 H2 + AgCl -> Ag + H+ + Cl-) at 27 deg C.
- -0.44 F
- -0.4 F
- -0.22 F
- -0.33 F
Correct answer: -0.22 F
Solution
T = 27 + 273 = 300 K. E = 0.4 - 2*10⁻⁶*(300)² = 0.4 - 0.18 = 0.22 V. The reaction 1/2 H2 + AgCl -> Ag + H+ + Cl- involves n=1 electron. delta G = -n*F*E = -1*F*0.22 = -0.22 F.
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