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ExamsJEE AdvancedChemistry

In the following electrochemical cell operating at 298 K: Pt(s) | H₂(g, 1 bar) | H⁺(aq, 1 M) || M⁴⁺(aq), M²⁺(aq) | Pt(s), the cell potential is measured to be 0.092 V when the ratio [M²⁺(aq)] / [M⁴⁺(aq)] equals 10^x. If the standard reduction potential of the M⁴⁺/M²⁺ couple is 0.151 V and 2.303 RT/F equals 0.059 V, determine the value of x.

  1. -2
  2. -1
  3. 1
  4. 2

Correct answer: 2

Solution

The Nernst equation relates the cell potential to the concentrations of the species involved. Substituting the given values, the equation simplifies to 0.092 = 0.151 - (0.059/2) log([M²⁺]/[M⁴⁺]). Solving for the ratio [M²⁺]/[M⁴⁺], we find x = 2.

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