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A conductivity cell filled with 0.05 M oxalic acid solution has a resistance of 200 ohm and a cell constant of 2.0 cm⁻¹. What is the equivalent conductance (in S cm² eq⁻¹) of this oxalic acid solution?
- 100
- 0.2
- 200
- 400
Correct answer: 100
Solution
Specific conductivity kappa = 2.0 / 200 = 0.01 S cm⁻¹. Oxalic acid is diprotic so N = 2 * 0.05 = 0.1 N. Equivalent conductance = 0.01 * 1000 / 0.1 = 100 S cm² eq⁻¹.
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