Exams › JEE Advanced › Chemistry
Correct answer: 6, 12, 8
SC: Each atom at a corner is touched by 6 atoms (one along each of +x, -x, +y, -y, +z, -z). Coordination number = 6. FCC: Each atom is surrounded by 12 nearest neighbours (4 in its own layer, 4 above, 4 below). Coordination number = 12. BCC: The atom at body centre has 8 nearest neighbours at the 8 corners, and vice versa. Coordination number = 8. Sequence SC, FCC, BCC = 6, 12, 8.