Exams › JEE Advanced › Chemistry
Correct answer: 3
O2 has 16 electrons. MO filling order: sigma(1s)², sigma*(1s)², sigma(2s)², sigma*(2s)², sigma(2p)², pi(2p)⁴, pi*(2p)². Antibonding MOs occupied: sigma*(1s) with 2e, sigma*(2s) with 2e, pi*(2p) with 2e = 6 electrons = 3 pairs.