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The equivalent conductivities of BaCl2, H2SO4, and HCl are x1, x2, and x3 S cm² eq⁻¹ respectively. The specific conductance of a saturated solution of BaSO4 is x S cm⁻¹. Express the solubility product Ksp of BaSO4 in terms of these quantities.
- 500x / (x1 + x2 - 2x3)
- 10⁶ x² / (x1 + x2 - 2x3)²
- 2.5 * 10⁵ x² / (x1 + x2 - x3)²
- 10⁶ x² / (x1 + x2 - 2x3)³
Correct answer: 10⁶ x² / (x1 + x2 - 2x3)²
Solution
By Kohlrausch's law, Lambda_inf(BaSO4) = x1 + x2 - 2x3. The equivalent concentration of BaSO4 in saturated solution: C_eq = specific conductance / Lambda_inf = x/(x1+x2-2x3) eq/cm³. Converting to mol/L: C_mol = (x*1000)/(x1+x2-2x3) mol/m³... careful with units.
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