Exams › JEE Advanced › Chemistry

Match the xenon compounds with the number of lone pairs on the central xenon atom and the hybridisation of xenon: Compound: (P) XeOF4, (Q) XeO2F2, (R) XeO3F2, (S) XeO6⁴- Lone pairs on Xe: (I) 1, (II) 0, (III) 3, (IV) 2 Hybridisation of Xe: (i) sp3, (ii) sp3d, (iii) sp3d2, (iv) sp3d3 Which combination is correct for XeOF4?

1. P with (I) lone pair and (iii) sp3d2 hybridisation
2. P with (I) lone pair and (ii) sp3d hybridisation
3. P with (I) lone pair and (i) sp3 hybridisation
4. None of the above

Correct answer: P with (I) lone pair and (iii) sp3d2 hybridisation

Solution

In XeOF4, xenon forms 4 bonds with F and 1 double bond (or coordinate bond) with O, with 1 remaining lone pair. Total electron domains = 6, so hybridisation is sp3d2. The lone pair count is 1, matching (I).

Related JEE Advanced Chemistry questions

• When N₂ is converted to N₂⁺, what happens to the bond dissociation energy of the N–N bond, and when O₂ is converted to O₂⁺, what happens to the bond dissociation energy of the O–O bond?
• In which of these ions is pπ–dπ bonding absent?
• What is the VSEPR formula for the chlorine trifluoride molecule?
• Consider the following molecules: CO2, SO2, and H2O. Arrange them in ascending order of their dipole moments.
• Which of the following occurrences is primarily influenced by hydrogen bonding?
• When two 1s atomic orbitals (one from each atom) combine to form molecular orbitals, which of the following statements is correct?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →